1+11pq-80p^2q^2=0

Solution for 1+11pq-80p^2q^2=0 equation:

Simplifying
1 + 11pq + -80p2q2 = 0

Solving
1 + 11pq + -80p2q2 = 0

Solving for variable 'p'.

Factor a trinomial.
(1 + -5pq)(1 + 16pq) = 0

Subproblem 1
Set the factor '(1 + -5pq)' equal to zero and attempt to solve:

Simplifying
1 + -5pq = 0

Solving
1 + -5pq = 0

Move all terms containing p to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -5pq = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -5pq = 0 + -1
-5pq = 0 + -1

Combine like terms: 0 + -1 = -1
-5pq = -1

Divide each side by '-5q'.
p = 0.2q-1

Simplifying
p = 0.2q-1
Subproblem 2
Set the factor '(1 + 16pq)' equal to zero and attempt to solve:

Simplifying
1 + 16pq = 0

Solving
1 + 16pq = 0

Move all terms containing p to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 16pq = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 16pq = 0 + -1
16pq = 0 + -1

Combine like terms: 0 + -1 = -1
16pq = -1

Divide each side by '16q'.
p = -0.0625q-1

Simplifying
p = -0.0625q-1
Solution
p = {0.2q-1, -0.0625q-1}